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- nairitabgocom
- May 16, 2022
- 2 min read

Jan 21, 2021
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Business In A Box Crack Serial Keygen - This keygen includes a large amount of useful documents.Q:
How can I get a constexpr string from a templated variable of string type
I am trying to write a parser with Boost Spirit that uses "regular" (for lack of a better word) lookahead similar to this:
auto start = str.begin();
auto end = str.end();
auto state = start;
// Then I parse something like this:
if (expression) {
state = expr.begin();
}
auto attr = *state;
// I want to get a reference to the attr for the expression,
// or, if it's not there, "something else".
I've written code like this:
template
T& operator->() {
return *this;
}
// For operators like =, %,..., etc.
The basic idea is that I want to be able to do:
auto state = foo.cbegin();
if (expr) {
auto attr = *state;
}
I can't figure out how to get the constexpr value of state, and I can't get T & operator->() to work because the first parameter is T, not T &.
One solution that doesn't quite work is to make it templated, like so:
template
constexpr T& operator->() {
return *this;
}
// For operators like =, %,..., etc.
template
T& foo::operator->() {
return *this;
}
// And then I get the same problems:
auto state = foo.cbegin();
if (expr) { be359ba680
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